2x-(1/3)x^2=0

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Solution for 2x-(1/3)x^2=0 equation: 



2x-(1/3)x^2=0



Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x-(+1/3)x^2=0

We multiply all the terms by the denominator


2x*3)x^2-(+1=0

Wy multiply elements

6x^2+1=0

a = 6; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·6·1
Δ = -24
Delta is less than zero, so there is no solution for the equation

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